Base | Representation |
---|---|
bin | 10111011000000000011… |
… | …000001011001110010010 |
3 | 12200120012111012100200020 |
4 | 113120000120023032102 |
5 | 202304222432344010 |
6 | 3225533552204310 |
7 | 224024131422162 |
oct | 27300030131622 |
9 | 5616174170606 |
10 | 1606324106130 |
11 | 56a269098a87 |
12 | 21b396839696 |
13 | b86251acc83 |
14 | 57a645865a2 |
15 | 2bbb68dd470 |
hex | 1760060b392 |
1606324106130 has 32 divisors (see below), whose sum is σ = 3907988515584. Its totient is φ = 422485243776.
The previous prime is 1606324106129. The next prime is 1606324106131. The reversal of 1606324106130 is 316014236061.
It is an interprime number because it is at equal distance from previous prime (1606324106129) and next prime (1606324106131).
It is a junction number, because it is equal to n+sod(n) for n = 1606324106091 and 1606324106100.
It is not an unprimeable number, because it can be changed into a prime (1606324106131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 366738474 + ... + 366742853.
It is an arithmetic number, because the mean of its divisors is an integer number (122124641112).
Almost surely, 21606324106130 is an apocalyptic number.
1606324106130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1606324106130 is an abundant number, since it is smaller than the sum of its proper divisors (2301664409454).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1606324106130 is a wasteful number, since it uses less digits than its factorization.
1606324106130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 733481410.
The product of its (nonzero) digits is 15552, while the sum is 33.
The spelling of 1606324106130 in words is "one trillion, six hundred six billion, three hundred twenty-four million, one hundred six thousand, one hundred thirty".
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