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16079798716433 is a prime number
BaseRepresentation
bin1110100111111101111010…
…1100001100100000010001
32002221012202211010121120122
43221333132230030200101
54101422411432411213
654110542455320025
73246504254635514
oct351773654144021
962835684117518
1016079798716433
11513a44a1a31a1
121978458080015
138c841aa0680a
143d83a305cd7b
151cd414889d08
hexe9fdeb0c811

16079798716433 has 2 divisors, whose sum is σ = 16079798716434. Its totient is φ = 16079798716432.

The previous prime is 16079798716411. The next prime is 16079798716441. The reversal of 16079798716433 is 33461789797061.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12391294096129 + 3688504620304 = 3520127^2 + 1920548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16079798716433 is a prime.

It is a super-2 number, since 2×160797987164332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (16079798716633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8039899358216 + 8039899358217.

It is an arithmetic number, because the mean of its divisors is an integer number (8039899358217).

Almost surely, 216079798716433 is an apocalyptic number.

It is an amenable number.

16079798716433 is a deficient number, since it is larger than the sum of its proper divisors (1).

16079798716433 is an equidigital number, since it uses as much as digits as its factorization.

16079798716433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288054144, while the sum is 71.

The spelling of 16079798716433 in words is "sixteen trillion, seventy-nine billion, seven hundred ninety-eight million, seven hundred sixteen thousand, four hundred thirty-three".