Base | Representation |
---|---|
bin | 1110101000000100001110… |
… | …0000100000000000010111 |
3 | 2002221101010200212022102001 |
4 | 3222001003200200000113 |
5 | 4101434342434240044 |
6 | 54111422400500131 |
7 | 3246564213610123 |
oct | 352010340400027 |
9 | 62841120768361 |
10 | 16081490149399 |
11 | 5140137a44884 |
12 | 197884a61a647 |
13 | 8c862a27381c |
14 | 3d84c3954583 |
15 | 1cd4b30ea2d4 |
hex | ea043820017 |
16081490149399 has 2 divisors, whose sum is σ = 16081490149400. Its totient is φ = 16081490149398.
The previous prime is 16081490149381. The next prime is 16081490149421. The reversal of 16081490149399 is 99394109418061.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16081490149399 - 215 = 16081490116631 is a prime.
It is a super-2 number, since 2×160814901493992 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 16081490149399.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16081490149499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8040745074699 + 8040745074700.
It is an arithmetic number, because the mean of its divisors is an integer number (8040745074700).
Almost surely, 216081490149399 is an apocalyptic number.
16081490149399 is a deficient number, since it is larger than the sum of its proper divisors (1).
16081490149399 is an equidigital number, since it uses as much as digits as its factorization.
16081490149399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15116544, while the sum is 64.
The spelling of 16081490149399 in words is "sixteen trillion, eighty-one billion, four hundred ninety million, one hundred forty-nine thousand, three hundred ninety-nine".
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