Base | Representation |
---|---|
bin | 1001010111110111001… |
… | …1010111000010010101 |
3 | 120101122001211100101001 |
4 | 2111331303113002111 |
5 | 10114234221440103 |
6 | 201550143503301 |
7 | 14430222602416 |
oct | 2257563270225 |
9 | 511561740331 |
10 | 161024405653 |
11 | 62321096301 |
12 | 2725a8b7b31 |
13 | 12252570607 |
14 | 7b179b580d |
15 | 42c689001d |
hex | 257dcd7095 |
161024405653 has 2 divisors, whose sum is σ = 161024405654. Its totient is φ = 161024405652.
The previous prime is 161024405639. The next prime is 161024405657. The reversal of 161024405653 is 356504420161.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 94250228004 + 66774177649 = 307002^2 + 258407^2 .
It is a cyclic number.
It is not a de Polignac number, because 161024405653 - 25 = 161024405621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (161024405657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80512202826 + 80512202827.
It is an arithmetic number, because the mean of its divisors is an integer number (80512202827).
Almost surely, 2161024405653 is an apocalyptic number.
It is an amenable number.
161024405653 is a deficient number, since it is larger than the sum of its proper divisors (1).
161024405653 is an equidigital number, since it uses as much as digits as its factorization.
161024405653 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 161024405653 in words is "one hundred sixty-one billion, twenty-four million, four hundred five thousand, six hundred fifty-three".
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