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16105544131 = 23369122507
BaseRepresentation
bin11101111111111011…
…10001100111000011
31112120102102102010111
432333331301213003
5230441004403011
611222045412151
71110052603105
oct167775614703
945512372114
1016105544131
116915183756
12315586a057
1316988bb391
14acada7575
15643de3121
hex3bff719c3

16105544131 has 4 divisors (see below), whose sum is σ = 16174666872. Its totient is φ = 16036421392.

The previous prime is 16105544101. The next prime is 16105544137. The reversal of 16105544131 is 13144550161.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 16105544131 - 223 = 16097155523 is a prime.

It is a super-2 number, since 2×161055441312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16105544093 and 16105544102.

It is not an unprimeable number, because it can be changed into a prime (16105544137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34561021 + ... + 34561486.

It is an arithmetic number, because the mean of its divisors is an integer number (4043666718).

Almost surely, 216105544131 is an apocalyptic number.

16105544131 is a deficient number, since it is larger than the sum of its proper divisors (69122741).

16105544131 is an equidigital number, since it uses as much as digits as its factorization.

16105544131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69122740.

The product of its (nonzero) digits is 7200, while the sum is 31.

The spelling of 16105544131 in words is "sixteen billion, one hundred five million, five hundred forty-four thousand, one hundred thirty-one".

Divisors: 1 233 69122507 16105544131