Base | Representation |
---|---|
bin | 1110101001011110111001… |
… | …1011001010000010111011 |
3 | 2010000200222011021021221212 |
4 | 3222113232123022002323 |
5 | 4102334221104123042 |
6 | 54130530045353335 |
7 | 3251415354231512 |
oct | 352275633120273 |
9 | 63020864237855 |
10 | 16105832489147 |
11 | 514a49961aa35 |
12 | 198150286884b |
13 | 8caa0947345b |
14 | 3d9752825679 |
15 | 1cde3a1b0482 |
hex | ea5ee6ca0bb |
16105832489147 has 2 divisors, whose sum is σ = 16105832489148. Its totient is φ = 16105832489146.
The previous prime is 16105832489143. The next prime is 16105832489177. The reversal of 16105832489147 is 74198423850161.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16105832489147 - 22 = 16105832489143 is a prime.
It is not a weakly prime, because it can be changed into another prime (16105832489143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8052916244573 + 8052916244574.
It is an arithmetic number, because the mean of its divisors is an integer number (8052916244574).
It is a 1-persistent number, because it is pandigital, but 2⋅16105832489147 = 32211664978294 is not.
Almost surely, 216105832489147 is an apocalyptic number.
16105832489147 is a deficient number, since it is larger than the sum of its proper divisors (1).
16105832489147 is an equidigital number, since it uses as much as digits as its factorization.
16105832489147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11612160, while the sum is 59.
The spelling of 16105832489147 in words is "sixteen trillion, one hundred five billion, eight hundred thirty-two million, four hundred eighty-nine thousand, one hundred forty-seven".
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