Search a number
-
+
16109113 is a prime number
BaseRepresentation
bin111101011100…
…111000111001
31010022102112211
4331130320321
513110442423
61333135121
7253632226
oct75347071
933272484
1016109113
119103019
12548a4a1
133450427
1421d494d
15163310d
hexf5ce39

16109113 has 2 divisors, whose sum is σ = 16109114. Its totient is φ = 16109112.

The previous prime is 16109101. The next prime is 16109143. The reversal of 16109113 is 31190161.

It is a happy number.

16109113 is nontrivially palindromic in base 11.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11648569 + 4460544 = 3413^2 + 2112^2 .

It is an emirp because it is prime and its reverse (31190161) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16109113 - 217 = 15978041 is a prime.

It is not a weakly prime, because it can be changed into another prime (16109143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8054556 + 8054557.

It is an arithmetic number, because the mean of its divisors is an integer number (8054557).

Almost surely, 216109113 is an apocalyptic number.

It is an amenable number.

16109113 is a deficient number, since it is larger than the sum of its proper divisors (1).

16109113 is an equidigital number, since it uses as much as digits as its factorization.

16109113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 22.

The square root of 16109113 is about 4013.6159507357. The cubic root of 16109113 is about 252.5557201476. Note that the first 3 decimals are identical.

Adding to 16109113 its reverse (31190161), we get a palindrome (47299274).

The spelling of 16109113 in words is "sixteen million, one hundred nine thousand, one hundred thirteen".