Base | Representation |
---|---|
bin | 1110101001110100001110… |
… | …0001011001000011010011 |
3 | 2010001020201222110210111211 |
4 | 3222131003201121003103 |
5 | 4102432431104413011 |
6 | 54133313554120551 |
7 | 3252010233126133 |
oct | 352350341310323 |
9 | 63036658423454 |
10 | 16111555154131 |
11 | 5151965947928 |
12 | 198263b280157 |
13 | 8cb40bc48858 |
14 | 3d9b36880ac3 |
15 | 1ce1727b4b21 |
hex | ea7438590d3 |
16111555154131 has 2 divisors, whose sum is σ = 16111555154132. Its totient is φ = 16111555154130.
The previous prime is 16111555154129. The next prime is 16111555154153. The reversal of 16111555154131 is 13145155511161.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16111555154131 - 21 = 16111555154129 is a prime.
It is a super-2 number, since 2×161115551541312 (a number of 27 digits) contains 22 as substring.
Together with 16111555154129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (16111535154131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8055777577065 + 8055777577066.
It is an arithmetic number, because the mean of its divisors is an integer number (8055777577066).
Almost surely, 216111555154131 is an apocalyptic number.
16111555154131 is a deficient number, since it is larger than the sum of its proper divisors (1).
16111555154131 is an equidigital number, since it uses as much as digits as its factorization.
16111555154131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 45000, while the sum is 40.
The spelling of 16111555154131 in words is "sixteen trillion, one hundred eleven billion, five hundred fifty-five million, one hundred fifty-four thousand, one hundred thirty-one".
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