Base | Representation |
---|---|
bin | 10111011100100110010… |
… | …000101011010111000001 |
3 | 12201000221002212112112001 |
4 | 113130212100223113001 |
5 | 202344322142021423 |
6 | 3232111122504001 |
7 | 224260251324514 |
oct | 27344620532701 |
9 | 5630832775461 |
10 | 1611254642113 |
11 | 571369270706 |
12 | 220331b05001 |
13 | b8c2c829c9c |
14 | 57db1324d7b |
15 | 2bda46c2cad |
hex | 1772642b5c1 |
1611254642113 has 2 divisors, whose sum is σ = 1611254642114. Its totient is φ = 1611254642112.
The previous prime is 1611254642089. The next prime is 1611254642143. The reversal of 1611254642113 is 3112464521161.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1597069117504 + 14185524609 = 1263752^2 + 119103^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1611254642113 is a prime.
It is a super-2 number, since 2×16112546421132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1611254642143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 805627321056 + 805627321057.
It is an arithmetic number, because the mean of its divisors is an integer number (805627321057).
Almost surely, 21611254642113 is an apocalyptic number.
It is an amenable number.
1611254642113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1611254642113 is an equidigital number, since it uses as much as digits as its factorization.
1611254642113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34560, while the sum is 37.
The spelling of 1611254642113 in words is "one trillion, six hundred eleven billion, two hundred fifty-four million, six hundred forty-two thousand, one hundred thirteen".
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