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1611254642143 is a prime number
BaseRepresentation
bin10111011100100110010…
…000101011010111011111
312201000221002212112120011
4113130212100223113133
5202344322142022033
63232111122504051
7224260251324556
oct27344620532737
95630832775504
101611254642143
11571369270733
12220331b05027
13b8c2c829cc3
1457db1324d9d
152bda46c2ccd
hex1772642b5df

1611254642143 has 2 divisors, whose sum is σ = 1611254642144. Its totient is φ = 1611254642142.

The previous prime is 1611254642113. The next prime is 1611254642201. The reversal of 1611254642143 is 3412464521161.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1611254642143 is a prime.

It is a super-2 number, since 2×16112546421432 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1611254642096 and 1611254642105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1611254642113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 805627321071 + 805627321072.

It is an arithmetic number, because the mean of its divisors is an integer number (805627321072).

Almost surely, 21611254642143 is an apocalyptic number.

1611254642143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1611254642143 is an equidigital number, since it uses as much as digits as its factorization.

1611254642143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 138240, while the sum is 40.

The spelling of 1611254642143 in words is "one trillion, six hundred eleven billion, two hundred fifty-four million, six hundred forty-two thousand, one hundred forty-three".