Base | Representation |
---|---|
bin | 10111011100100110010… |
… | …000101011010111011111 |
3 | 12201000221002212112120011 |
4 | 113130212100223113133 |
5 | 202344322142022033 |
6 | 3232111122504051 |
7 | 224260251324556 |
oct | 27344620532737 |
9 | 5630832775504 |
10 | 1611254642143 |
11 | 571369270733 |
12 | 220331b05027 |
13 | b8c2c829cc3 |
14 | 57db1324d9d |
15 | 2bda46c2ccd |
hex | 1772642b5df |
1611254642143 has 2 divisors, whose sum is σ = 1611254642144. Its totient is φ = 1611254642142.
The previous prime is 1611254642113. The next prime is 1611254642201. The reversal of 1611254642143 is 3412464521161.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1611254642143 is a prime.
It is a super-2 number, since 2×16112546421432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1611254642096 and 1611254642105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1611254642113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 805627321071 + 805627321072.
It is an arithmetic number, because the mean of its divisors is an integer number (805627321072).
Almost surely, 21611254642143 is an apocalyptic number.
1611254642143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1611254642143 is an equidigital number, since it uses as much as digits as its factorization.
1611254642143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 138240, while the sum is 40.
The spelling of 1611254642143 in words is "one trillion, six hundred eleven billion, two hundred fifty-four million, six hundred forty-two thousand, one hundred forty-three".
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