16117113 has 4 divisors (see below), whose sum is σ = 21489488. Its totient is φ = 10744740.

The previous prime is 16117103. The next prime is 16117121. The reversal of 16117113 is 31171161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 16117113 - 2⁵ = 16117081 is a prime.

It is a super-2 number, since 2×16117113² = 519522662909538, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 16117113.

It is not an unprimeable number, because it can be changed into a prime (16117103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2686183 + ... + 2686188.

It is an arithmetic number, because the mean of its divisors is an integer number (5372372).

Almost surely, 2^16117113 is an apocalyptic number.

It is an amenable number.

16117113 is a deficient number, since it is larger than the sum of its proper divisors (5372375).

16117113 is an equidigital number, since it uses as much as digits as its factorization.

16117113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5372374.

The product of its digits is 126, while the sum is 21.

The square root of 16117113 is about 4014.6124345944. The cubic root of 16117113 is about 252.5975207399.

Adding to 16117113 its reverse (31171161), we get a palindrome (47288274).

The spelling of 16117113 in words is "sixteen million, one hundred seventeen thousand, one hundred thirteen".