Base | Representation |
---|---|
bin | 11110000001111000… |
… | …10101000001110101 |
3 | 1112121120021111221220 |
4 | 33000330111001311 |
5 | 231004204122013 |
6 | 11223433100553 |
7 | 1110342150513 |
oct | 170074250165 |
9 | 45546244856 |
10 | 16121942133 |
11 | 6923463820 |
12 | 315b257759 |
13 | 169c11013b |
14 | acd2354b3 |
15 | 645581b23 |
hex | 3c0f15075 |
16121942133 has 16 divisors (see below), whose sum is σ = 23691855936. Its totient is φ = 9670141440.
The previous prime is 16121942087. The next prime is 16121942171. The reversal of 16121942133 is 33124912161.
It is not a de Polignac number, because 16121942133 - 222 = 16117747829 is a prime.
It is a super-3 number, since 3×161219421333 (a number of 32 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 16121942094 and 16121942103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16121942173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2515066 + ... + 2521467.
It is an arithmetic number, because the mean of its divisors is an integer number (1480740996).
Almost surely, 216121942133 is an apocalyptic number.
It is an amenable number.
16121942133 is a deficient number, since it is larger than the sum of its proper divisors (7569913803).
16121942133 is a wasteful number, since it uses less digits than its factorization.
16121942133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5036644.
The product of its digits is 7776, while the sum is 33.
The spelling of 16121942133 in words is "sixteen billion, one hundred twenty-one million, nine hundred forty-two thousand, one hundred thirty-three".
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