Base | Representation |
---|---|
bin | 10111011101100001000… |
… | …101110010001110101011 |
3 | 12201010110220002100101122 |
4 | 113131201011302032223 |
5 | 202403332330024121 |
6 | 3232353101405455 |
7 | 224323564563431 |
oct | 27354105621653 |
9 | 5633426070348 |
10 | 1612241642411 |
11 | 571825415634 |
12 | 22056856988b |
13 | b905916512a |
14 | 5806644ad51 |
15 | 2be111875ab |
hex | 177611723ab |
1612241642411 has 2 divisors, whose sum is σ = 1612241642412. Its totient is φ = 1612241642410.
The previous prime is 1612241642359. The next prime is 1612241642413. The reversal of 1612241642411 is 1142461422161.
It is a strong prime.
It is an emirp because it is prime and its reverse (1142461422161) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1612241642411 is a prime.
It is a super-2 number, since 2×16122416424112 (a number of 25 digits) contains 22 as substring.
Together with 1612241642413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1612241642413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 806120821205 + 806120821206.
It is an arithmetic number, because the mean of its divisors is an integer number (806120821206).
Almost surely, 21612241642411 is an apocalyptic number.
1612241642411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1612241642411 is an equidigital number, since it uses as much as digits as its factorization.
1612241642411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18432, while the sum is 35.
The spelling of 1612241642411 in words is "one trillion, six hundred twelve billion, two hundred forty-one million, six hundred forty-two thousand, four hundred eleven".
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