Base | Representation |
---|---|
bin | 1110101010100011000100… |
… | …1110100110111010010001 |
3 | 2010002110012120011210101100 |
4 | 3222220301032212322101 |
5 | 4103134211041022121 |
6 | 54143154032055013 |
7 | 3252634023223152 |
oct | 352506116467221 |
9 | 63073176153340 |
10 | 16124133142161 |
11 | 515722a892460 |
12 | 1984b6b694469 |
13 | 8cc664a6cb15 |
14 | 3da5ab155929 |
15 | 1ce65bb56026 |
hex | eaa313a6e91 |
16124133142161 has 48 divisors (see below), whose sum is σ = 26654048853120. Its totient is φ = 9302338752000.
The previous prime is 16124133142157. The next prime is 16124133142207.
16124133142161 is a `hidden beast` number, since 1 + 6 + 1 + 241 + 331 + 4 + 21 + 61 = 666.
16124133142161 is nontrivially palindromic in base 10.
16124133142161 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 16124133142161 - 22 = 16124133142157 is a prime.
It is a super-2 number, since 2×161241331421612 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (16124133142111) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 39346920 + ... + 39754601.
It is an arithmetic number, because the mean of its divisors is an integer number (555292684440).
Almost surely, 216124133142161 is an apocalyptic number.
16124133142161 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
16124133142161 is a deficient number, since it is larger than the sum of its proper divisors (10529915710959).
16124133142161 is a wasteful number, since it uses less digits than its factorization.
16124133142161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79101638 (or 79101635 counting only the distinct ones).
The product of its digits is 20736, while the sum is 36.
It can be divided in two parts, 1612413 and 3142161, that added together give a palindrome (4754574).
The spelling of 16124133142161 in words is "sixteen trillion, one hundred twenty-four billion, one hundred thirty-three million, one hundred forty-two thousand, one hundred sixty-one".
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