Base | Representation |
---|---|
bin | 11110000010010010… |
… | …10110010001111011 |
3 | 1112121210200220201020 |
4 | 33001021112101323 |
5 | 231011042331011 |
6 | 11224034153523 |
7 | 1110413154114 |
oct | 170111262173 |
9 | 45553626636 |
10 | 16125355131 |
11 | 6925384a86 |
12 | 31604228a3 |
13 | 169ca36772 |
14 | acd88320b |
15 | 645a08006 |
hex | 3c125647b |
16125355131 has 16 divisors (see below), whose sum is σ = 22491826944. Its totient is φ = 10256916384.
The previous prime is 16125355097. The next prime is 16125355153. The reversal of 16125355131 is 13155352161.
16125355131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 16125355131 - 210 = 16125354107 is a prime.
It is a super-2 number, since 2×161253551312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16125355092 and 16125355101.
It is not an unprimeable number, because it can be changed into a prime (16125355231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 266941 + ... + 321726.
It is an arithmetic number, because the mean of its divisors is an integer number (1405739184).
Almost surely, 216125355131 is an apocalyptic number.
16125355131 is a deficient number, since it is larger than the sum of its proper divisors (6366471813).
16125355131 is a wasteful number, since it uses less digits than its factorization.
16125355131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 589090.
The product of its digits is 13500, while the sum is 33.
The spelling of 16125355131 in words is "sixteen billion, one hundred twenty-five million, three hundred fifty-five thousand, one hundred thirty-one".
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