16125521401 has 4 divisors (see below), whose sum is σ = 17591477904. Its totient is φ = 14659564900.

The previous prime is 16125521393. The next prime is 16125521417. The reversal of 16125521401 is 10412552161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16125521401 - 2³ = 16125521393 is a prime.

It is a super-3 number, since 3×16125521401³ (a number of 32 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 16125521401.

It is not an unprimeable number, because it can be changed into a prime (16125521101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 732978235 + ... + 732978256.

It is an arithmetic number, because the mean of its divisors is an integer number (4397869476).

Almost surely, 2^16125521401 is an apocalyptic number.

16125521401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

16125521401 is a deficient number, since it is larger than the sum of its proper divisors (1465956503).

16125521401 is a wasteful number, since it uses less digits than its factorization.

16125521401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1465956502.

The product of its (nonzero) digits is 2400, while the sum is 28.

The spelling of 16125521401 in words is "sixteen billion, one hundred twenty-five million, five hundred twenty-one thousand, four hundred one".