16128950674843 has 2 divisors, whose sum is σ = 16128950674844. Its totient is φ = 16128950674842.

The previous prime is 16128950674841. The next prime is 16128950674871. The reversal of 16128950674843 is 34847605982161.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 16128950674843 - 2¹ = 16128950674841 is a prime.

It is a super-2 number, since 2×16128950674843² (a number of 27 digits) contains 22 as substring.

Together with 16128950674841, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (16128950674841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8064475337421 + 8064475337422.

It is an arithmetic number, because the mean of its divisors is an integer number (8064475337422).

It is a 2-persistent number, because it is pandigital, and so is 2⋅16128950674843 = 32257901349686, but 3⋅16128950674843 = 48386852024529 is not.

Almost surely, 2^{16128950674843} is an apocalyptic number.

16128950674843 is a deficient number, since it is larger than the sum of its proper divisors (1).

16128950674843 is an equidigital number, since it uses as much as digits as its factorization.

16128950674843 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69672960, while the sum is 64.

The spelling of 16128950674843 in words is "sixteen trillion, one hundred twenty-eight billion, nine hundred fifty million, six hundred seventy-four thousand, eight hundred forty-three".