Base | Representation |
---|---|
bin | 1110101010111001001000… |
… | …0101111111101010110111 |
3 | 2010010000111010212222222211 |
4 | 3222232102011333222313 |
5 | 4103233322112212102 |
6 | 54150013312234251 |
7 | 3253233520231111 |
oct | 352562205775267 |
9 | 63100433788884 |
10 | 16130053241527 |
11 | 51597985aa765 |
12 | 198614223b987 |
13 | 9000994117b4 |
14 | 3da9ad4c63b1 |
15 | 1ce8a67597d7 |
hex | eab9217fab7 |
16130053241527 has 2 divisors, whose sum is σ = 16130053241528. Its totient is φ = 16130053241526.
The previous prime is 16130053241509. The next prime is 16130053241587. The reversal of 16130053241527 is 72514235003161.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16130053241527 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16130053241527.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16130053241587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8065026620763 + 8065026620764.
It is an arithmetic number, because the mean of its divisors is an integer number (8065026620764).
Almost surely, 216130053241527 is an apocalyptic number.
16130053241527 is a deficient number, since it is larger than the sum of its proper divisors (1).
16130053241527 is an equidigital number, since it uses as much as digits as its factorization.
16130053241527 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
Adding to 16130053241527 its reverse (72514235003161), we get a palindrome (88644288244688).
The spelling of 16130053241527 in words is "sixteen trillion, one hundred thirty billion, fifty-three million, two hundred forty-one thousand, five hundred twenty-seven".
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