Base | Representation |
---|---|
bin | 1001011000111011011… |
… | …0110010010010110011 |
3 | 120102101000012021112111 |
4 | 2112032312302102303 |
5 | 10120330443011103 |
6 | 202034404110151 |
7 | 14440265523511 |
oct | 2261666622263 |
9 | 512330167474 |
10 | 161310516403 |
11 | 62458643573 |
12 | 2731a695357 |
13 | 1229991750a |
14 | 7b439b14b1 |
15 | 42e1a5886d |
hex | 258edb24b3 |
161310516403 has 4 divisors (see below), whose sum is σ = 161938184040. Its totient is φ = 160682848768.
The previous prime is 161310516383. The next prime is 161310516413. The reversal of 161310516403 is 304615013161.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304615013161 = 23 ⋅13244131007.
It is a cyclic number.
It is not a de Polignac number, because 161310516403 - 217 = 161310385331 is a prime.
It is a super-3 number, since 3×1613105164033 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (161310516413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 313833433 + ... + 313833946.
It is an arithmetic number, because the mean of its divisors is an integer number (40484546010).
Almost surely, 2161310516403 is an apocalyptic number.
161310516403 is a deficient number, since it is larger than the sum of its proper divisors (627667637).
161310516403 is an equidigital number, since it uses as much as digits as its factorization.
161310516403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 627667636.
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 161310516403 its reverse (304615013161), we get a palindrome (465925529564).
The spelling of 161310516403 in words is "one hundred sixty-one billion, three hundred ten million, five hundred sixteen thousand, four hundred three".
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