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161322019 is a prime number
BaseRepresentation
bin10011001110110…
…01010000100011
3102020120000012121
421213121100203
5312244301034
624001405111
73666133405
oct1147312043
9366500177
10161322019
1183075691
1246039797
1327564421
14175d4b75
15e2691b4
hex99d9423

161322019 has 2 divisors, whose sum is σ = 161322020. Its totient is φ = 161322018.

The previous prime is 161322013. The next prime is 161322067. The reversal of 161322019 is 910223161.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 161322019 - 29 = 161321507 is a prime.

It is a super-2 number, since 2×1613220192 = 52049587628472722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 161321984 and 161322002.

It is not a weakly prime, because it can be changed into another prime (161322013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80661009 + 80661010.

It is an arithmetic number, because the mean of its divisors is an integer number (80661010).

Almost surely, 2161322019 is an apocalyptic number.

161322019 is a deficient number, since it is larger than the sum of its proper divisors (1).

161322019 is an equidigital number, since it uses as much as digits as its factorization.

161322019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 161322019 is about 12701.2605279948. The cubic root of 161322019 is about 544.3746371865.

It can be divided in two parts, 1613 and 22019, that added together give a palindrome (23632).

The spelling of 161322019 in words is "one hundred sixty-one million, three hundred twenty-two thousand, nineteen".