Base | Representation |
---|---|
bin | 11110000011011111… |
… | …01011101001110111 |
3 | 1112122111121110101011 |
4 | 33001233223221313 |
5 | 231021130413101 |
6 | 11225033413051 |
7 | 1110564446416 |
oct | 170157535167 |
9 | 45574543334 |
10 | 16135404151 |
11 | 6930018a59 |
12 | 316386a187 |
13 | 16a1b44729 |
14 | ad0d3b47d |
15 | 646840751 |
hex | 3c1beba77 |
16135404151 has 4 divisors (see below), whose sum is σ = 16510646152. Its totient is φ = 15760162152.
The previous prime is 16135404149. The next prime is 16135404209. The reversal of 16135404151 is 15140453161.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15140453161 = 4019 ⋅3767219.
It is a cyclic number.
It is not a de Polignac number, because 16135404151 - 21 = 16135404149 is a prime.
It is a super-2 number, since 2×161354041512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16135404101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187620936 + ... + 187621021.
It is an arithmetic number, because the mean of its divisors is an integer number (4127661538).
Almost surely, 216135404151 is an apocalyptic number.
16135404151 is a deficient number, since it is larger than the sum of its proper divisors (375242001).
16135404151 is an equidigital number, since it uses as much as digits as its factorization.
16135404151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 375242000.
The product of its (nonzero) digits is 7200, while the sum is 31.
The spelling of 16135404151 in words is "sixteen billion, one hundred thirty-five million, four hundred four thousand, one hundred fifty-one".
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