Base | Representation |
---|---|
bin | 1001011001010001110… |
… | …1010100101111011011 |
3 | 120102121120001101201112 |
4 | 2112110131110233123 |
5 | 10121024023130201 |
6 | 202052002410535 |
7 | 14442516441056 |
oct | 2262435245733 |
9 | 512546041645 |
10 | 161404505051 |
11 | 624a66a9639 |
12 | 27346060a4b |
13 | 122b3234aba |
14 | 7b52279a9d |
15 | 42e9e220bb |
hex | 2594754bdb |
161404505051 has 2 divisors, whose sum is σ = 161404505052. Its totient is φ = 161404505050.
The previous prime is 161404505039. The next prime is 161404505083. The reversal of 161404505051 is 150505404161.
It is an a-pointer prime, because the next prime (161404505083) can be obtained adding 161404505051 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-161404505051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 161404504999 and 161404505017.
It is not a weakly prime, because it can be changed into another prime (161404505011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80702252525 + 80702252526.
It is an arithmetic number, because the mean of its divisors is an integer number (80702252526).
Almost surely, 2161404505051 is an apocalyptic number.
161404505051 is a deficient number, since it is larger than the sum of its proper divisors (1).
161404505051 is an equidigital number, since it uses as much as digits as its factorization.
161404505051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 161404505051 in words is "one hundred sixty-one billion, four hundred four million, five hundred five thousand, fifty-one".
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