1614054424341 has 4 divisors (see below), whose sum is σ = 2152072565792. Its totient is φ = 1076036282892.

The previous prime is 1614054424289. The next prime is 1614054424427. The reversal of 1614054424341 is 1434244504161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1614054424341 - 2²¹ = 1614052327189 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1614054424341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1614054424441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 269009070721 + ... + 269009070726.

It is an arithmetic number, because the mean of its divisors is an integer number (538018141448).

Almost surely, 2^{1614054424341} is an apocalyptic number.

It is an amenable number.

1614054424341 is a deficient number, since it is larger than the sum of its proper divisors (538018141451).

1614054424341 is an equidigital number, since it uses as much as digits as its factorization.

1614054424341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 538018141450.

The product of its (nonzero) digits is 184320, while the sum is 39.

The spelling of 1614054424341 in words is "one trillion, six hundred fourteen billion, fifty-four million, four hundred twenty-four thousand, three hundred forty-one".