Base | Representation |
---|---|
bin | 1001011001010010111… |
… | …1111110111100101011 |
3 | 120102121220020220120011 |
4 | 2112110233332330223 |
5 | 10121031301142043 |
6 | 202052255312351 |
7 | 14442606142654 |
oct | 2262457767453 |
9 | 512556226504 |
10 | 161409396523 |
11 | 624a943a681 |
12 | 2734781b6b7 |
13 | 122b425836b |
14 | 7b52b9052b |
15 | 42ea58b59d |
hex | 2594bfef2b |
161409396523 has 2 divisors, whose sum is σ = 161409396524. Its totient is φ = 161409396522.
The previous prime is 161409396493. The next prime is 161409396553. The reversal of 161409396523 is 325693904161.
It is a balanced prime because it is at equal distance from previous prime (161409396493) and next prime (161409396553).
It is an emirp because it is prime and its reverse (325693904161) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 161409396523 - 213 = 161409388331 is a prime.
It is not a weakly prime, because it can be changed into another prime (161409396553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80704698261 + 80704698262.
It is an arithmetic number, because the mean of its divisors is an integer number (80704698262).
Almost surely, 2161409396523 is an apocalyptic number.
161409396523 is a deficient number, since it is larger than the sum of its proper divisors (1).
161409396523 is an equidigital number, since it uses as much as digits as its factorization.
161409396523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1049760, while the sum is 49.
The spelling of 161409396523 in words is "one hundred sixty-one billion, four hundred nine million, three hundred ninety-six thousand, five hundred twenty-three".
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