Base | Representation |
---|---|
bin | 11110000100001101… |
… | …11101000111100001 |
3 | 1112122221002102011021 |
4 | 33002012331013201 |
5 | 231024211124433 |
6 | 11225412245441 |
7 | 1111000346215 |
oct | 170206750741 |
9 | 45587072137 |
10 | 16141504993 |
11 | 6933505679 |
12 | 3165910881 |
13 | 16a319c5b3 |
14 | ad1a88945 |
15 | 64714822d |
hex | 3c21bd1e1 |
16141504993 has 2 divisors, whose sum is σ = 16141504994. Its totient is φ = 16141504992.
The previous prime is 16141504987. The next prime is 16141504997. The reversal of 16141504993 is 39940514161.
16141504993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9636759889 + 6504745104 = 98167^2 + 80652^2 .
It is a cyclic number.
It is not a de Polignac number, because 16141504993 - 25 = 16141504961 is a prime.
It is not a weakly prime, because it can be changed into another prime (16141504997) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8070752496 + 8070752497.
It is an arithmetic number, because the mean of its divisors is an integer number (8070752497).
Almost surely, 216141504993 is an apocalyptic number.
It is an amenable number.
16141504993 is a deficient number, since it is larger than the sum of its proper divisors (1).
16141504993 is an equidigital number, since it uses as much as digits as its factorization.
16141504993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 116640, while the sum is 43.
The spelling of 16141504993 in words is "sixteen billion, one hundred forty-one million, five hundred four thousand, nine hundred ninety-three".
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