16143110133 has 4 divisors (see below), whose sum is σ = 21524146848. Its totient is φ = 10762073420.

The previous prime is 16143110131. The next prime is 16143110147. The reversal of 16143110133 is 33101134161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33101134161 = 3 ⋅11033711387.

It is a cyclic number.

It is not a de Polignac number, because 16143110133 - 2¹ = 16143110131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16143110131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2690518353 + ... + 2690518358.

It is an arithmetic number, because the mean of its divisors is an integer number (5381036712).

Almost surely, 2^16143110133 is an apocalyptic number.

It is an amenable number.

16143110133 is a deficient number, since it is larger than the sum of its proper divisors (5381036715).

16143110133 is an equidigital number, since it uses as much as digits as its factorization.

16143110133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5381036714.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 16143110133 its reverse (33101134161), we get a palindrome (49244244294).

The spelling of 16143110133 in words is "sixteen billion, one hundred forty-three million, one hundred ten thousand, one hundred thirty-three".