Base | Representation |
---|---|
bin | 1001011001011011100… |
… | …0001100011100000001 |
3 | 120102201101110000010122 |
4 | 2112112320030130001 |
5 | 10121114421301421 |
6 | 202100012510025 |
7 | 14443521510353 |
oct | 2262670143401 |
9 | 512641400118 |
10 | 161445103361 |
11 | 62517608763 |
12 | 2735777b315 |
13 | 122bb77aa79 |
14 | 7b578070d3 |
15 | 42ed7912ab |
hex | 2596e0c701 |
161445103361 has 2 divisors, whose sum is σ = 161445103362. Its totient is φ = 161445103360.
The previous prime is 161445103331. The next prime is 161445103363. The reversal of 161445103361 is 163301544161.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 160184853361 + 1260250000 = 400231^2 + 35500^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-161445103361 is a prime.
Together with 161445103363, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (161445103363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80722551680 + 80722551681.
It is an arithmetic number, because the mean of its divisors is an integer number (80722551681).
Almost surely, 2161445103361 is an apocalyptic number.
It is an amenable number.
161445103361 is a deficient number, since it is larger than the sum of its proper divisors (1).
161445103361 is an equidigital number, since it uses as much as digits as its factorization.
161445103361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 161445103361 in words is "one hundred sixty-one billion, four hundred forty-five million, one hundred three thousand, three hundred sixty-one".
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