Base | Representation |
---|---|
bin | 1001011001100001110… |
… | …0010101100100101101 |
3 | 120102210012211201212021 |
4 | 2112120130111210231 |
5 | 10121143131331211 |
6 | 202102351310141 |
7 | 14444260605313 |
oct | 2263034254455 |
9 | 512705751767 |
10 | 161471355181 |
11 | 62530409084 |
12 | 2736451b351 |
13 | 122c403c9a6 |
14 | 7b5b0bc0b3 |
15 | 4300c29771 |
hex | 259871592d |
161471355181 has 2 divisors, whose sum is σ = 161471355182. Its totient is φ = 161471355180.
The previous prime is 161471355131. The next prime is 161471355211. The reversal of 161471355181 is 181553174161.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115457244100 + 46014111081 = 339790^2 + 214509^2 .
It is a cyclic number.
It is not a de Polignac number, because 161471355181 - 211 = 161471353133 is a prime.
It is a super-2 number, since 2×1614713551812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (161471355131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80735677590 + 80735677591.
It is an arithmetic number, because the mean of its divisors is an integer number (80735677591).
Almost surely, 2161471355181 is an apocalyptic number.
It is an amenable number.
161471355181 is a deficient number, since it is larger than the sum of its proper divisors (1).
161471355181 is an equidigital number, since it uses as much as digits as its factorization.
161471355181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 100800, while the sum is 43.
The spelling of 161471355181 in words is "one hundred sixty-one billion, four hundred seventy-one million, three hundred fifty-five thousand, one hundred eighty-one".
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