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16149944113 is a prime number
BaseRepresentation
bin11110000101001110…
…01001011100110001
31112200111222011110021
433002213021130301
5231033341202423
611230313203441
71111132155112
oct170247113461
945614864407
1016149944113
11693824a056
123168700581
1316a4b65864
14ad2c44209
15647c6395d
hex3c29c9731

16149944113 has 2 divisors, whose sum is σ = 16149944114. Its totient is φ = 16149944112.

The previous prime is 16149944077. The next prime is 16149944119. The reversal of 16149944113 is 31144994161.

16149944113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14790694689 + 1359249424 = 121617^2 + 36868^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16149944113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 16149944113.

It is not a weakly prime, because it can be changed into another prime (16149944119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8074972056 + 8074972057.

It is an arithmetic number, because the mean of its divisors is an integer number (8074972057).

Almost surely, 216149944113 is an apocalyptic number.

It is an amenable number.

16149944113 is a deficient number, since it is larger than the sum of its proper divisors (1).

16149944113 is an equidigital number, since it uses as much as digits as its factorization.

16149944113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 93312, while the sum is 43.

The spelling of 16149944113 in words is "sixteen billion, one hundred forty-nine million, nine hundred forty-four thousand, one hundred thirteen".