Base | Representation |
---|---|
bin | 1110101100000111111010… |
… | …0011011001011010100010 |
3 | 2010012001001220200220011011 |
4 | 3223001332203121122202 |
5 | 4104110124230210224 |
6 | 54203431534011134 |
7 | 3254612540611525 |
oct | 353017643313242 |
9 | 63161056626134 |
10 | 16151200241314 |
11 | 516775a525696 |
12 | 198a264346aaa |
13 | 902089614a18 |
14 | 3dba17c62bbc |
15 | 1d01e3042394 |
hex | eb07e8d96a2 |
16151200241314 has 4 divisors (see below), whose sum is σ = 24226800361974. Its totient is φ = 8075600120656.
The previous prime is 16151200241303. The next prime is 16151200241399. The reversal of 16151200241314 is 41314200215161.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13395709800225 + 2755490441089 = 3660015^2 + 1659967^2 .
It is a super-2 number, since 2×161512002413142 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4037800060327 + ... + 4037800060330.
Almost surely, 216151200241314 is an apocalyptic number.
16151200241314 is a deficient number, since it is larger than the sum of its proper divisors (8075600120660).
16151200241314 is an equidigital number, since it uses as much as digits as its factorization.
16151200241314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8075600120659.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 16151200241314 its reverse (41314200215161), we get a palindrome (57465400456475).
The spelling of 16151200241314 in words is "sixteen trillion, one hundred fifty-one billion, two hundred million, two hundred forty-one thousand, three hundred fourteen".
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