Base | Representation |
---|---|
bin | 1110101100101100110100… |
… | …1110010100010001011011 |
3 | 2010012222122112202022220011 |
4 | 3223023031032110101123 |
5 | 4104240423133044013 |
6 | 54212151135342351 |
7 | 3255413241602641 |
oct | 353131516242133 |
9 | 63188575668804 |
10 | 16161110049883 |
11 | 5170985338527 |
12 | 199016b0819b7 |
13 | 902ca8714086 |
14 | 3dc2b8029191 |
15 | 1d05c3036c3d |
hex | eb2cd39445b |
16161110049883 has 2 divisors, whose sum is σ = 16161110049884. Its totient is φ = 16161110049882.
The previous prime is 16161110049767. The next prime is 16161110049907. The reversal of 16161110049883 is 38894001116161.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16161110049883 is a prime.
It is a super-2 number, since 2×161611100498832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16161111049883) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8080555024941 + 8080555024942.
It is an arithmetic number, because the mean of its divisors is an integer number (8080555024942).
Almost surely, 216161110049883 is an apocalyptic number.
16161110049883 is a deficient number, since it is larger than the sum of its proper divisors (1).
16161110049883 is an equidigital number, since it uses as much as digits as its factorization.
16161110049883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 248832, while the sum is 49.
The spelling of 16161110049883 in words is "sixteen trillion, one hundred sixty-one billion, one hundred ten million, forty-nine thousand, eight hundred eighty-three".
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