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16163413103 is a prime number
BaseRepresentation
bin11110000110110101…
…00001110001101111
31112201110022110102202
433003122201301233
5231100313204403
611231514012115
71111354513235
oct170332416157
945643273382
1016163413103
116944909552
12317111703b
1316a78a0386
14ad494c955
15649024688
hex3c36a1c6f

16163413103 has 2 divisors, whose sum is σ = 16163413104. Its totient is φ = 16163413102.

The previous prime is 16163413099. The next prime is 16163413177. The reversal of 16163413103 is 30131436161.

It is a weak prime.

It is an emirp because it is prime and its reverse (30131436161) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16163413103 - 22 = 16163413099 is a prime.

It is a super-3 number, since 3×161634131033 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16163413403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8081706551 + 8081706552.

It is an arithmetic number, because the mean of its divisors is an integer number (8081706552).

Almost surely, 216163413103 is an apocalyptic number.

16163413103 is a deficient number, since it is larger than the sum of its proper divisors (1).

16163413103 is an equidigital number, since it uses as much as digits as its factorization.

16163413103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 16163413103 its reverse (30131436161), we get a palindrome (46294849264).

The spelling of 16163413103 in words is "sixteen billion, one hundred sixty-three million, four hundred thirteen thousand, one hundred three".