Base | Representation |
---|---|
bin | 100100110000011001101010… |
… | …001101010000011101000011 |
3 | 210012101010202221001010110212 |
4 | 210300121222031100131003 |
5 | 132142031444300301021 |
6 | 1331451344212344335 |
7 | 46023146312126462 |
oct | 4460315215203503 |
9 | 705333687033425 |
10 | 161655760947011 |
11 | 47565906774551 |
12 | 16169b773150ab |
13 | 6c280c4077166 |
14 | 2bcc2757089d9 |
15 | 13a5085e6385b |
hex | 93066a350743 |
161655760947011 has 2 divisors, whose sum is σ = 161655760947012. Its totient is φ = 161655760947010.
The previous prime is 161655760946987. The next prime is 161655760947013. The reversal of 161655760947011 is 110749067556161.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-161655760947011 is a prime.
It is a super-2 number, since 2×1616557609470112 (a number of 29 digits) contains 22 as substring.
Together with 161655760947013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (161655760947013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80827880473505 + 80827880473506.
It is an arithmetic number, because the mean of its divisors is an integer number (80827880473506).
Almost surely, 2161655760947011 is an apocalyptic number.
161655760947011 is a deficient number, since it is larger than the sum of its proper divisors (1).
161655760947011 is an equidigital number, since it uses as much as digits as its factorization.
161655760947011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9525600, while the sum is 59.
The spelling of 161655760947011 in words is "one hundred sixty-one trillion, six hundred fifty-five billion, seven hundred sixty million, nine hundred forty-seven thousand, eleven".
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