Base | Representation |
---|---|
bin | 1110101101000000111011… |
… | …1001000000101101011011 |
3 | 2010020111120122112222220221 |
4 | 3223100032321000231123 |
5 | 4104333001210301113 |
6 | 54214442441100511 |
7 | 3255664051606132 |
oct | 353201671005533 |
9 | 63214518488827 |
10 | 16166506728283 |
11 | 51731a465191a |
12 | 1991216487737 |
13 | 9036587c03c2 |
14 | 3dc66aa68919 |
15 | 1d07dbbe798d |
hex | eb40ee40b5b |
16166506728283 has 2 divisors, whose sum is σ = 16166506728284. Its totient is φ = 16166506728282.
The previous prime is 16166506728277. The next prime is 16166506728349. The reversal of 16166506728283 is 38282760566161.
It is a happy number.
16166506728283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16166506728283 - 233 = 16157916793691 is a prime.
It is a super-3 number, since 3×161665067282833 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (16166506728233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8083253364141 + 8083253364142.
It is an arithmetic number, because the mean of its divisors is an integer number (8083253364142).
Almost surely, 216166506728283 is an apocalyptic number.
16166506728283 is a deficient number, since it is larger than the sum of its proper divisors (1).
16166506728283 is an equidigital number, since it uses as much as digits as its factorization.
16166506728283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34836480, while the sum is 61.
The spelling of 16166506728283 in words is "sixteen trillion, one hundred sixty-six billion, five hundred six million, seven hundred twenty-eight thousand, two hundred eighty-three".
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