Base | Representation |
---|---|
bin | 1001011010111010001… |
… | …1100000001101100001 |
3 | 120110202001220100002110 |
4 | 2112232203200031201 |
5 | 10122423114120023 |
6 | 202203242505533 |
7 | 14456414062011 |
oct | 2265643401541 |
9 | 513661810073 |
10 | 161842332513 |
11 | 62700860914 |
12 | 274488052a9 |
13 | 12352b5c0c4 |
14 | 7b94489c41 |
15 | 43235a8a93 |
hex | 25ae8e0361 |
161842332513 has 4 divisors (see below), whose sum is σ = 215789776688. Its totient is φ = 107894888340.
The previous prime is 161842332461. The next prime is 161842332517. The reversal of 161842332513 is 315233248161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 161842332513 - 210 = 161842331489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (161842332517) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26973722083 + ... + 26973722088.
It is an arithmetic number, because the mean of its divisors is an integer number (53947444172).
Almost surely, 2161842332513 is an apocalyptic number.
It is an amenable number.
161842332513 is a deficient number, since it is larger than the sum of its proper divisors (53947444175).
161842332513 is an equidigital number, since it uses as much as digits as its factorization.
161842332513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53947444174.
The product of its digits is 103680, while the sum is 39.
The spelling of 161842332513 in words is "one hundred sixty-one billion, eight hundred forty-two million, three hundred thirty-two thousand, five hundred thirteen".
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