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162022457113 = 1114729314283
BaseRepresentation
bin1001011011100101001…
…0100111111100011001
3120111012121211121120221
42112321102213330121
510123310222111423
6202233155320041
714464032106426
oct2267122477431
9514177747527
10162022457113
11627934a9120
1227498bb0021
13123812778ca
147bb0376d4d
1543342d8e5d
hex25b94a7f19

162022457113 has 4 divisors (see below), whose sum is σ = 176751771408. Its totient is φ = 147293142820.

The previous prime is 162022457101. The next prime is 162022457131. The reversal of 162022457113 is 311754220261.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 162022457113 - 25 = 162022457081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (162022457213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7364657131 + ... + 7364657152.

It is an arithmetic number, because the mean of its divisors is an integer number (44187942852).

Almost surely, 2162022457113 is an apocalyptic number.

It is an amenable number.

162022457113 is a deficient number, since it is larger than the sum of its proper divisors (14729314295).

162022457113 is a wasteful number, since it uses less digits than its factorization.

162022457113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14729314294.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 162022457113 its reverse (311754220261), we get a palindrome (473776677374).

The spelling of 162022457113 in words is "one hundred sixty-two billion, twenty-two million, four hundred fifty-seven thousand, one hundred thirteen".

Divisors: 1 11 14729314283 162022457113