Base | Representation |
---|---|
bin | 10111100101101010001… |
… | …011000111100110100011 |
3 | 12201222001011022121121011 |
4 | 113211222023013212203 |
5 | 203024233344021321 |
6 | 3240400400041351 |
7 | 225053331256534 |
oct | 27455213074643 |
9 | 5658034277534 |
10 | 1620983970211 |
11 | 575501212931 |
12 | 2221a8303257 |
13 | b9b20417868 |
14 | 5865554a68b |
15 | 2c273916ae1 |
hex | 1796a2c79a3 |
1620983970211 has 2 divisors, whose sum is σ = 1620983970212. Its totient is φ = 1620983970210.
The previous prime is 1620983970191. The next prime is 1620983970223. The reversal of 1620983970211 is 1120793890261.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1620983970211 - 27 = 1620983970083 is a prime.
It is a super-2 number, since 2×16209839702112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1320983970211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 810491985105 + 810491985106.
It is an arithmetic number, because the mean of its divisors is an integer number (810491985106).
Almost surely, 21620983970211 is an apocalyptic number.
1620983970211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1620983970211 is an equidigital number, since it uses as much as digits as its factorization.
1620983970211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 49.
The spelling of 1620983970211 in words is "one trillion, six hundred twenty billion, nine hundred eighty-three million, nine hundred seventy thousand, two hundred eleven".
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