Base | Representation |
---|---|
bin | 10111100101101011010… |
… | …101110011110110100001 |
3 | 12201222002112011101011201 |
4 | 113211223111303312201 |
5 | 203024303402100423 |
6 | 3240402335441201 |
7 | 225053656556023 |
oct | 27455325636641 |
9 | 5658075141151 |
10 | 1621003550113 |
11 | 575511276572 |
12 | 2221b2986201 |
13 | b9b244b19bc |
14 | 58657da6013 |
15 | 2c2754d32ad |
hex | 1796b573da1 |
1621003550113 has 2 divisors, whose sum is σ = 1621003550114. Its totient is φ = 1621003550112.
The previous prime is 1621003550071. The next prime is 1621003550141. The reversal of 1621003550113 is 3110553001261.
It is an a-pointer prime, because the next prime (1621003550141) can be obtained adding 1621003550113 to its sum of digits (28).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1536689974689 + 84313575424 = 1239633^2 + 290368^2 .
It is a cyclic number.
It is not a de Polignac number, because 1621003550113 - 229 = 1620466679201 is a prime.
It is not a weakly prime, because it can be changed into another prime (1621003554113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 810501775056 + 810501775057.
It is an arithmetic number, because the mean of its divisors is an integer number (810501775057).
Almost surely, 21621003550113 is an apocalyptic number.
It is an amenable number.
1621003550113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1621003550113 is an equidigital number, since it uses as much as digits as its factorization.
1621003550113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 1621003550113 its reverse (3110553001261), we get a palindrome (4731556551374).
The spelling of 1621003550113 in words is "one trillion, six hundred twenty-one billion, three million, five hundred fifty thousand, one hundred thirteen".
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