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16214232308147 is a prime number
BaseRepresentation
bin1110101111110010101110…
…0011101001100110110011
32010102001202201122122122222
43223330223203221212303
54111123221432330042
654252414313551255
73262303535416316
oct353745343514663
963361681578588
1016214232308147
115191465485405
12199a51571552b
13907cc32a30a3
14400ab72a897d
151d1b81a702d2
hexebf2b8e99b3

16214232308147 has 2 divisors, whose sum is σ = 16214232308148. Its totient is φ = 16214232308146.

The previous prime is 16214232308119. The next prime is 16214232308149. The reversal of 16214232308147 is 74180323241261.

It is a strong prime.

It is an emirp because it is prime and its reverse (74180323241261) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16214232308147 - 218 = 16214232046003 is a prime.

Together with 16214232308149, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 16214232308098 and 16214232308107.

It is not a weakly prime, because it can be changed into another prime (16214232308149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8107116154073 + 8107116154074.

It is an arithmetic number, because the mean of its divisors is an integer number (8107116154074).

Almost surely, 216214232308147 is an apocalyptic number.

16214232308147 is a deficient number, since it is larger than the sum of its proper divisors (1).

16214232308147 is an equidigital number, since it uses as much as digits as its factorization.

16214232308147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 387072, while the sum is 44.

The spelling of 16214232308147 in words is "sixteen trillion, two hundred fourteen billion, two hundred thirty-two million, three hundred eight thousand, one hundred forty-seven".