Base | Representation |
---|---|
bin | 1110110000110111000111… |
… | …0000111111011111111111 |
3 | 2010110211011010001002101222 |
4 | 3230031301300333133333 |
5 | 4111423321030024444 |
6 | 54305052100423555 |
7 | 3263523500045126 |
oct | 354156160773777 |
9 | 63424133032358 |
10 | 16232590079999 |
11 | 5199225a10087 |
12 | 19a1b996a7bbb |
13 | 90995a67b197 |
14 | 401939426abd |
15 | 1d23a8549eee |
hex | ec371c3f7ff |
16232590079999 has 4 divisors (see below), whose sum is σ = 16232767323360. Its totient is φ = 16232412836640.
The previous prime is 16232590079989. The next prime is 16232590080059. The reversal of 16232590079999 is 99997009523261.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16232590079999 - 232 = 16228295112703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16232590079989) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88484234 + ... + 88667495.
It is an arithmetic number, because the mean of its divisors is an integer number (4058191830840).
Almost surely, 216232590079999 is an apocalyptic number.
16232590079999 is a deficient number, since it is larger than the sum of its proper divisors (177243361).
16232590079999 is an equidigital number, since it uses as much as digits as its factorization.
16232590079999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177243360.
The product of its (nonzero) digits is 148803480, while the sum is 71.
The spelling of 16232590079999 in words is "sixteen trillion, two hundred thirty-two billion, five hundred ninety million, seventy-nine thousand, nine hundred ninety-nine".
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