Base | Representation |
---|---|
bin | 1110110001010111010111… |
… | …1100011101110111001001 |
3 | 2010111122111122110021121111 |
4 | 3230111311330131313021 |
5 | 4112044040013201101 |
6 | 54313043255410321 |
7 | 3264251214214321 |
oct | 354256574356711 |
9 | 63448448407544 |
10 | 16241250131401 |
11 | 51a196a321959 |
12 | 19a37b59839a1 |
13 | 90a70a884359 |
14 | 40211b62a281 |
15 | 1d2713976251 |
hex | ec575f1ddc9 |
16241250131401 has 2 divisors, whose sum is σ = 16241250131402. Its totient is φ = 16241250131400.
The previous prime is 16241250131387. The next prime is 16241250131417. The reversal of 16241250131401 is 10413105214261.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12955644366025 + 3285605765376 = 3599395^2 + 1812624^2 .
It is a cyclic number.
It is not a de Polignac number, because 16241250131401 - 25 = 16241250131369 is a prime.
It is not a weakly prime, because it can be changed into another prime (16241250131461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8120625065700 + 8120625065701.
It is an arithmetic number, because the mean of its divisors is an integer number (8120625065701).
Almost surely, 216241250131401 is an apocalyptic number.
It is an amenable number.
16241250131401 is a deficient number, since it is larger than the sum of its proper divisors (1).
16241250131401 is an equidigital number, since it uses as much as digits as its factorization.
16241250131401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 16241250131401 its reverse (10413105214261), we get a palindrome (26654355345662).
The spelling of 16241250131401 in words is "sixteen trillion, two hundred forty-one billion, two hundred fifty million, one hundred thirty-one thousand, four hundred one".
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