Base | Representation |
---|---|
bin | 1110110001010111010111… |
… | …1100011101110111011001 |
3 | 2010111122111122110021122002 |
4 | 3230111311330131313121 |
5 | 4112044040013201132 |
6 | 54313043255410345 |
7 | 3264251214214343 |
oct | 354256574356731 |
9 | 63448448407562 |
10 | 16241250131417 |
11 | 51a196a321973 |
12 | 19a37b59839b5 |
13 | 90a70a88436c |
14 | 40211b62a293 |
15 | 1d2713976262 |
hex | ec575f1ddd9 |
16241250131417 has 2 divisors, whose sum is σ = 16241250131418. Its totient is φ = 16241250131416.
The previous prime is 16241250131401. The next prime is 16241250131419. The reversal of 16241250131417 is 71413105214261.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14701519073536 + 1539731057881 = 3834256^2 + 1240859^2 .
It is a cyclic number.
It is not a de Polignac number, because 16241250131417 - 24 = 16241250131401 is a prime.
Together with 16241250131419, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (16241250131419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8120625065708 + 8120625065709.
It is an arithmetic number, because the mean of its divisors is an integer number (8120625065709).
Almost surely, 216241250131417 is an apocalyptic number.
It is an amenable number.
16241250131417 is a deficient number, since it is larger than the sum of its proper divisors (1).
16241250131417 is an equidigital number, since it uses as much as digits as its factorization.
16241250131417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 38.
Adding to 16241250131417 its reverse (71413105214261), we get a palindrome (87654355345678).
The spelling of 16241250131417 in words is "sixteen trillion, two hundred forty-one billion, two hundred fifty million, one hundred thirty-one thousand, four hundred seventeen".
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