16246139953 has 4 divisors (see below), whose sum is σ = 16952493888. Its totient is φ = 15539786020.

The previous prime is 16246139951. The next prime is 16246139993. The reversal of 16246139953 is 35993164261.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16246139953 - 2¹ = 16246139951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16246139897 and 16246139906.

It is not an unprimeable number, because it can be changed into a prime (16246139951) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353176933 + ... + 353176978.

It is an arithmetic number, because the mean of its divisors is an integer number (4238123472).

Almost surely, 2^16246139953 is an apocalyptic number.

It is an amenable number.

16246139953 is a deficient number, since it is larger than the sum of its proper divisors (706353935).

16246139953 is an equidigital number, since it uses as much as digits as its factorization.

16246139953 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 706353934.

The product of its digits is 1049760, while the sum is 49.

The spelling of 16246139953 in words is "sixteen billion, two hundred forty-six million, one hundred thirty-nine thousand, nine hundred fifty-three".