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1625134721141 is a prime number
BaseRepresentation
bin10111101001100001100…
…100111110100001110101
312202100202102200121110002
4113221201210332201311
5203111233442034031
63242324313041045
7225261232131311
oct27514144764165
95670672617402
101625134721141
115772412014a8
12222b663b6185
13ba33233bbb9
145892a902b41
152c418018ccb
hex17a6193e875

1625134721141 has 2 divisors, whose sum is σ = 1625134721142. Its totient is φ = 1625134721140.

The previous prime is 1625134721053. The next prime is 1625134721167. The reversal of 1625134721141 is 1411274315261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1523965560100 + 101169161041 = 1234490^2 + 318071^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1625134721141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1625134721095 and 1625134721104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1625134721941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 812567360570 + 812567360571.

It is an arithmetic number, because the mean of its divisors is an integer number (812567360571).

Almost surely, 21625134721141 is an apocalyptic number.

It is an amenable number.

1625134721141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1625134721141 is an equidigital number, since it uses as much as digits as its factorization.

1625134721141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 40320, while the sum is 38.

The spelling of 1625134721141 in words is "one trillion, six hundred twenty-five billion, one hundred thirty-four million, seven hundred twenty-one thousand, one hundred forty-one".