Base | Representation |
---|---|
bin | 11110010010000010… |
… | …01010011000001001 |
3 | 1112222000012212012012 |
4 | 33021001022120021 |
5 | 231243400130303 |
6 | 11245113025305 |
7 | 1113605564135 |
oct | 171101123011 |
9 | 45860185165 |
10 | 16257426953 |
11 | 6992991549 |
12 | 31986b5235 |
13 | 16c11c9281 |
14 | b032223c5 |
15 | 6523e55d8 |
hex | 3c904a609 |
16257426953 has 2 divisors, whose sum is σ = 16257426954. Its totient is φ = 16257426952.
The previous prime is 16257426949. The next prime is 16257427001. The reversal of 16257426953 is 35962475261.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13545933769 + 2711493184 = 116387^2 + 52072^2 .
It is a cyclic number.
It is not a de Polignac number, because 16257426953 - 22 = 16257426949 is a prime.
It is a super-2 number, since 2×162574269532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16257426253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8128713476 + 8128713477.
It is an arithmetic number, because the mean of its divisors is an integer number (8128713477).
Almost surely, 216257426953 is an apocalyptic number.
It is an amenable number.
16257426953 is a deficient number, since it is larger than the sum of its proper divisors (1).
16257426953 is an equidigital number, since it uses as much as digits as its factorization.
16257426953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2721600, while the sum is 50.
The spelling of 16257426953 in words is "sixteen billion, two hundred fifty-seven million, four hundred twenty-six thousand, nine hundred fifty-three".
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