Base | Representation |
---|---|
bin | 1110110011000101100110… |
… | …1110111011011001111111 |
3 | 2010121110212221000012111022 |
4 | 3230301121232323121333 |
5 | 4113040140421411143 |
6 | 54334415455214355 |
7 | 3266346423402446 |
oct | 354613156733177 |
9 | 63543787005438 |
10 | 16270841591423 |
11 | 5203474997841 |
12 | 19a9493b173bb |
13 | 910445407a03 |
14 | 4037276c9d5d |
15 | 1d33967a1268 |
hex | ecc59bbb67f |
16270841591423 has 2 divisors, whose sum is σ = 16270841591424. Its totient is φ = 16270841591422.
The previous prime is 16270841591393. The next prime is 16270841591479. The reversal of 16270841591423 is 32419514807261.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16270841591423 - 26 = 16270841591359 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16270841531423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8135420795711 + 8135420795712.
It is an arithmetic number, because the mean of its divisors is an integer number (8135420795712).
It is a 1-persistent number, because it is pandigital, but 2⋅16270841591423 = 32541683182846 is not.
Almost surely, 216270841591423 is an apocalyptic number.
16270841591423 is a deficient number, since it is larger than the sum of its proper divisors (1).
16270841591423 is an equidigital number, since it uses as much as digits as its factorization.
16270841591423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2903040, while the sum is 53.
The spelling of 16270841591423 in words is "sixteen trillion, two hundred seventy billion, eight hundred forty-one million, five hundred ninety-one thousand, four hundred twenty-three".
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