Base | Representation |
---|---|
bin | 10111101101001010011… |
… | …110001000001101011001 |
3 | 12202201211201221210212201 |
4 | 113231022132020031121 |
5 | 203142234224021423 |
6 | 3244212132010201 |
7 | 225460115450620 |
oct | 27551236101531 |
9 | 5681751853781 |
10 | 1629042017113 |
11 | 578966827825 |
12 | 223876a60961 |
13 | ba8059a2954 |
14 | 58bbb8046b7 |
15 | 2c59607b2ad |
hex | 17b4a788359 |
1629042017113 has 4 divisors (see below), whose sum is σ = 1861762305280. Its totient is φ = 1396321728948.
The previous prime is 1629042017081. The next prime is 1629042017129. The reversal of 1629042017113 is 3117102409261.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1629042017113 - 25 = 1629042017081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1629042012113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116360144073 + ... + 116360144086.
It is an arithmetic number, because the mean of its divisors is an integer number (465440576320).
Almost surely, 21629042017113 is an apocalyptic number.
It is an amenable number.
1629042017113 is a deficient number, since it is larger than the sum of its proper divisors (232720288167).
1629042017113 is an equidigital number, since it uses as much as digits as its factorization.
1629042017113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 232720288166.
The product of its (nonzero) digits is 18144, while the sum is 37.
The spelling of 1629042017113 in words is "one trillion, six hundred twenty-nine billion, forty-two million, seventeen thousand, one hundred thirteen".
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