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1631330114 = 2815665057
BaseRepresentation
bin110000100111100…
…0001111101000010
311012200122011012212
41201033001331002
511320110030424
6425513022122
755266035321
oct14117017502
94180564185
101631330114
11767930507
123963b4942
131ccc852bb
1411692c0b8
159833c10e
hex613c1f42

1631330114 has 4 divisors (see below), whose sum is σ = 2446995174. Its totient is φ = 815665056.

The previous prime is 1631330023. The next prime is 1631330123. The reversal of 1631330114 is 4110331361.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1318924489 + 312405625 = 36317^2 + 17675^2 .

It is a super-2 number, since 2×16313301142 = 5322475881686505992, which contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1631330114.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 407832527 + ... + 407832530.

Almost surely, 21631330114 is an apocalyptic number.

1631330114 is a deficient number, since it is larger than the sum of its proper divisors (815665060).

1631330114 is an equidigital number, since it uses as much as digits as its factorization.

1631330114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 815665059.

The product of its (nonzero) digits is 648, while the sum is 23.

The square root of 1631330114 is about 40389.7278277534. The cubic root of 1631330114 is about 1177.1919522104.

Adding to 1631330114 its reverse (4110331361), we get a palindrome (5741661475).

The spelling of 1631330114 in words is "one billion, six hundred thirty-one million, three hundred thirty thousand, one hundred fourteen".

Divisors: 1 2 815665057 1631330114