16341152313 has 4 divisors (see below), whose sum is σ = 21788203088. Its totient is φ = 10894101540.

The previous prime is 16341152281. The next prime is 16341152341. The reversal of 16341152313 is 31325114361.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31325114361 = 3 ⋅10441704787.

It is not a de Polignac number, because 16341152313 - 2⁵ = 16341152281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16341150313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2723525383 + ... + 2723525388.

It is an arithmetic number, because the mean of its divisors is an integer number (5447050772).

Almost surely, 2^16341152313 is an apocalyptic number.

It is an amenable number.

16341152313 is a deficient number, since it is larger than the sum of its proper divisors (5447050775).

16341152313 is an equidigital number, since it uses as much as digits as its factorization.

16341152313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5447050774.

The product of its digits is 6480, while the sum is 30.

Adding to 16341152313 its reverse (31325114361), we get a palindrome (47666266674).

The spelling of 16341152313 in words is "sixteen billion, three hundred forty-one million, one hundred fifty-two thousand, three hundred thirteen".