Base | Representation |
---|---|
bin | 1110110111110001010100… |
… | …1010001100100101100011 |
3 | 2010220011112220012201211121 |
4 | 3231330111022030211203 |
5 | 4120344423121143103 |
6 | 54435403105353111 |
7 | 3305225226302626 |
oct | 355742512144543 |
9 | 63804486181747 |
10 | 16351295490403 |
11 | 5234600032945 |
12 | 1a00ba7938797 |
13 | 917bc75a30b3 |
14 | 40759a859dbd |
15 | 1d5504a2d6bd |
hex | edf1528c963 |
16351295490403 has 2 divisors, whose sum is σ = 16351295490404. Its totient is φ = 16351295490402.
The previous prime is 16351295490379. The next prime is 16351295490499. The reversal of 16351295490403 is 30409459215361.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16351295490403 - 221 = 16351293393251 is a prime.
It is not a weakly prime, because it can be changed into another prime (16351295490703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8175647745201 + 8175647745202.
It is an arithmetic number, because the mean of its divisors is an integer number (8175647745202).
Almost surely, 216351295490403 is an apocalyptic number.
16351295490403 is a deficient number, since it is larger than the sum of its proper divisors (1).
16351295490403 is an equidigital number, since it uses as much as digits as its factorization.
16351295490403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3499200, while the sum is 52.
The spelling of 16351295490403 in words is "sixteen trillion, three hundred fifty-one billion, two hundred ninety-five million, four hundred ninety thousand, four hundred three".
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